(-3q^2+7q-12)/(q-2)

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Solution for (-3q^2+7q-12)/(q-2) equation: 


D( q )

q-2 = 0

q-2 = 0

q-2 = 0

q-2 = 0 // + 2

q = 2

q in (-oo:2) U (2:+oo)

(7*q-3*q^2-12)/(q-2) = 0

7*q-3*q^2-12 = 0

7*q-3*q^2-12 = 0

DELTA = 7^2-(-12*(-3)*4)

DELTA = -95

DELTA < 0

1 = 0

1/(q-2) = 0

q belongs to the empty set

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